Consider that calcium metal react next to oxygen gas contained by the atmosphere to form calcium oxide?

Suppose we react 6.00 mol calcium with 4.00 mol oxygen gas. Determine the number of moles of calcium gone over after the reaction is complete
Answers:
If the reaction go to completion, no calcium will be left over; 1.00 mol oxygen gas will be left over, however.

Consider the hanging chemical equation for this reaction:

2Ca + O2 --> 2CaO

We can calculate the number of moles of oxygen obligatory to completely react with the 6.00 mol calcium.

6.00 mol Ca x (1 mol O2)/(2 mol Ca) = 3.00 mol O2

Since here is excess oxygen, the calcium will react completely with one mole of O2 departed over.

I hope this helps! Source(s): My pencil and paper.

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